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A thick-walled cylinder subjected to external or internal pressure, or both, has radial and tangential stress with values which are dependent upon the radius of the element under consideration. A thick-walled cylinder may also be stressed longitudinally. In design, gun barrels, high-pressure hydraulic cylinders, and pipes carrying fluids at high pressures, must all be considered as thick-walled cylinders.
In determining the radial stress sigma_r and the tangential stress sigma_t, we make use of the assumption that the longitudinal elongation is constant around the circumference of the cylinder. In other words, a right section of the cylinder remains plane after stressing.
Referring to Figure [2-26], we designate the inside radius of the cylinder by a, the outside radius by b, the internal pressure by p_i, and the external pressure by p_o. Let us consider the equilibrium of an infinitely thin semicircular ring cut from the cylinder at radius r and having a unit length. Taking a summation of forces in the vertical direction equal to zero, we have
2*sigma_t*dr + 2*sigma_r*r - 2*(sigma_r+dsigma_r) * (r+dr) = 0 [a]Simplifying and neglecting higher-order quantities gives
sigma_t - sigma_r - r* dsigma_r/dr = 0 [b]Equation [b] relates the two unknowns sigma_t and sigma_r, but we must obtain a second relation in order to evaluate them. The second equation is obtained from the assumption that the longitudinal deformation is constant. Since both sigma_t and sigma_r are positive for tension, equation [2-22] can be written
epsilon_l = - mu * sigma_t / E - mu * sigma_r / E [c]where mu is Poisson's ratio and epsilon_l is the longitudinal unit deformation. Both of these are constants, and so equation [c] can be rearranged in the form
- E*epsilon_l/mu = sigma_t + sigma_r = 2 * C1 [d]
Next, solving equations [b] and [c] to eliminate sigma_t produces
r*dsigma_r/dr + 2*sigma_r = 2*C1 [e]Multiplying equation [e] by r gives
r^2*dsigma_r/dr + 2*r*sigma_r = 2*r*C1 [f]We note that
d/dr*(r^2*sigma_r) = r^2*dsigma_r/dr + 2*r*sigma_r [g]Therefore
d/dr*(r^2*sigma_r) = 2*r*C1 [h]which, when integrated, gives
r^2*sigma_r = r^2*C1 + C2 [i]where C2 is a constant of integration. Solving for sigma_r, we obtain
sigma_r = C1 + C2 / r^2 [j]Substituting this value in equation [d], we find
sigma_t = C1 - C2 / r^2 [k]
To evaluate the constants of integration, note that, at the boundaries of the cylinder,
sigma_r = -p_i at r = a sigma_r = -p_o at r = bSubstituting these values in equation [j] yields
-p_i = C1 + C2/a^2 -p_o = C1 + C2/b^2 [l]The constants are found by solving these two equations simultaneously. This gives
C1 = (p_i*a^2-p_o*b^2)/(b^2-a^2) C2 = a^2*b^2*(p_o-p_i)/(b^2-a^2) [m]Substituting these values into equations [j] and [k] yields
sigma_t = (p_i*a^2 - p_o*b^2 - a^2*b^2* (p_o-p_i)/r^2) / (b^2 - a^2) [2-53] sigma_r = (p_i*a^2 - p_o*b^2 + a^2*b^2* (p_o-p_i)/r^2) / (b^2 - a^2) [2-54]In the previous equations positive stresses indicate tension and negative stresses compression.
Let us now determine the stresses when the external pressure is zero. Substitution of p_o = 0 in equations [2-53] and [2-54] gives
sigma_t = a^2*p_i/(b^2-a^2)*(1+b^2/r^2) [2-55] sigma_r = a^2*p_i/(b^2-a^2)*(1-b^2/r^2) [2-56]These equations are plotted in Figure [2-27] to show the distribution of stresses over the wall thickness. The maximum stresses occur at the inner surface, where r=a. There magnitudes are
sigma_t = p_i*(b^2+a^2)/(b^2-a^2) [2-57] sigma_r = -p_i [2-58]The stresses in the outer surface of a cylinder subjected only to external pressure are found similarly. They are
Sigma_t = -p_o*(b^2+a^2)/(b^2-a^2) [2-59] Sigma_r = -p_o [2-60]This section of the book is UNDER CONSTRUCTION...
Mechanical Engineering Design Section 2-15 Stresses in Thick-Walled Cylinders
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